Explanation:
Solution:
Given,
t1( first term ) a = -15
t2( second term ) b = -9
CD(Common Difference) = ?
We know,
CD = b - a
= -9 - ( - 15 )
= -9 + 15
= 6
Now,
t1 = -15
t2 = -9
t3 = -3
t4 = 3
t5 = a + ( n - 1 )CD
= -15 + ( 5 - 1 ) 6
= -15 + 24
= 9
t50 = a + (n - 1 ) CD
= -15 + ( 50 - 1 ) CD
= -15 + 49 × 6
= -15 + 284
= 269
So the sum of t50 is 269.