Final answer:
To compare the mean tensile strengths at the 95% confidence level, we perform a two-sample t-test. The calculated t-value is compared to the critical t-value from the t-distribution table. The null hypothesis is not rejected, indicating no significant difference in mean tensile strengths.
Step-by-step explanation:
To compare the mean tensile strengths at the 95% confidence level, we need to perform a hypothesis test. The null hypothesis (H0) is that there is no difference in the mean tensile strengths between the no fusion and yes fusion processes. The alternative hypothesis (Ha) is that there is a difference in the mean tensile strengths.
Finally, we compare the t-value to the critical t-value from the t-distribution table. For a 95% confidence level with 15 degrees of freedom (n1 + n2 - 2), the critical t-value is approximately 2.131. Since the calculated t-value (-1.8073) is less than the critical t-value (2.131), we fail to reject the null hypothesis. Therefore, we conclude that there is not enough evidence to suggest a significant difference in the mean tensile strengths between the no fusion and yes fusion processes at the 95% confidence level.