Question

At what pressure would a 5.32 mol Cl2 sample occupy 5.08 L at 181.59 K? please help!!

Answer 1

Answer: At a pressure of 15.613 atm a 5.32 mol
`Cl_(2)` sample occupy 5.08 L at 181.59 K.

Step-by-step explanation:

Given: Moles = 5.32 mol

Volume = 5.08 L

Temperature = 181.59 K

Formula used to calculate the pressure is as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

`PV = nRT\\P * 5.08 L = 5.32 mol * 0.0821 L atm/mol K * 181.59 K\\P = (5.32 mol * 0.0821 L atm/mol K * 181.59 K)/(5.08 L)\\= 15.613 atm`

Thus, we can conclude that at a pressure of 15.613 atm a 5.32 mol
`Cl_(2)` sample occupy 5.08 L at 181.59 K.