204k views
1 vote
9. Assuming all other conditions are constant, what is the new pressure of a gas if the original pressure is 50 kPa and the Kelvin temperature is doubled?

a.100kpa
b.25kpa
or D.200kpa​

1 Answer

4 votes

Answer:

Option a (100 kPa) is the appropriate option.

Step-by-step explanation:

The given value is:

Original pressure,

P₁ = 50 kPa

Let the new pressure be "x".

Now,


(P1)/(T_1) =(P_2)/(T_2)

On substituting the values, we get


(50)/(T_1) =(x)/(2T_1)

On applying cross-multiplication, we get


x = 50* 2


=100 \ kPa

Thus the answer above is the right one.

User Denis Kohl
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.