Question

A virologist has a cell-free extract of herpes simplex virus (HSV) that has a titer of 6 x 106 infectious virus particles/mL. This virus forms plaques on monolayers of the monkey kidney cell line, CV-1. Following completion of a 10-fold dilution series, the virologist plates 100 microliters of each sample in duplicate.

Required:
What experimental results did he MOST LIKELY observe in the duplicate plates corresponding to his 1:10000 dilution?

Answer 1

61 for Plate 1 ,

59 for Plate 2

Explanation:

Given that the original stock has a concentration of 6 * 10^6 infectious virus particles /mL

and it was diluted by 1:10000

New concentration = ( 6 * 10^6 ) / 10000 = 600 infectious virus particles/ mL

Also given that the virologist plates 100 mL of each sample

therefore; 0.1 mL has a count of 60.

The experimental results that he is most likely to observe in the duplicate plates will be ;

61 for (Plate 1) ,

59 for (Plate 2)