Question

The left side of a solid block is held at a constant temperature of 200°C. The temperature profile within the block is given by T=200−5x−x2 where x is the distance from the left side of the block in centimeters and T is the temperature in degrees Celsius of the block at location x. At what value of x is T=50°C?

Answer 1

with T = 50⁰C, we have:

50 = 200 - 5x - x²

<=> x² + 5x = 150

<=> x² + 5x - 150 = 0

=> x = 10