Question

Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 2 L, the pressure is 1100 kPa (kilopascals). What is the pressure when the volume is 11 L?

Answer 1

P1V1=P2V2

1100.2=P2.11

P2=200 kPa

Answer 2

".. the volume of a gas varies inversely with the pressure"

implies that

V =k/P, where k is a constant

given: when V=4, P = 165

4 = k/165

k = 660

so we have : V = 660/P

when P = 60

V = 660/60 = 11

or

the volume of a gas varies inversely with the pressure

V1/V2 = P2/P1

4/V2 = 60/165

60V2 = 660

V2 = 660/60 = 11