Answer:
Ni2+ is reduced at the cathode.
The anode reaction could be Cr -> Cr3+ + 3e-
As the cell runs, anions will migrate from the Ni2+|Ni compartment to the other compartment.
Step-by-step explanation:
As we know, in a galvanic cell, oxidation occurs at the anode and reduction occurs at the cathode. Hence at the cathode, nickel is reduced as follows;
Ni^2+(aq) + 2e ----> Ni(s)
Considering the reduction potential of the Ni2+ | Ni half cell (-0.25 V) and that of the Cr3+/Cr half cell (-0.74 V), the later has a more negative reduction potential and will most likely serve as the anode of the galvanic cell.
Lastly, the reduction of Ni^2+ leads to a build up of anions in the cathode compartment. To maintain neutrality in the cell, some anions migrate to the other compartment.