Answer:
a) Its first term, a₁ -1,190
b) Its second term, a₂ = -1,186
c) Its third term, a₃ = -1,182
Explanation:
The 100th term of the arithmetic progression, AP = 406
The common difference of the AP = 4
The formula to find the nth term of an AP, aₙ is given as follows;
aₙ = a + (n - 1)·d
Where;
aₙ = The nth term of the AP
a = The first term of the AP
a) Given the 400th term and the common difference, we have;
a₄₀₀ = 406 = a + (400 - 1) × 4
406 = a + 399 × 4
a = 406 - 399 × 4 = -1,190
The first term of the AP, a = -1,190
b) The second term of the AP, a₂ = -1,190 + (2 - 1) × 4 = -1,186
The second term of the AP, a₂ = -1,186
c) The third term of the AP, a₃ = -1,190 + (3 - 1) × 4 = -1,182
The third term of the AP, a₃ = -1,182.