Question

A discarded spray paint can contains only a small volume of the propellant gas at a

pressure of 34.5 kPa. The volume of the can is 473 ml. If the can is run over by the
garbage truck and flattened to a volume of 13.16 ml, what is the pressure in kPa
assuming the can doesn't leak?

Answer 1

1.24 × 10³ kPa

Step-by-step explanation:

Step 1: Given data

• Initial pressure of the gas (P₁): 34.5 kPa

• Initial volume of the can (V₁): 473 mL

• Final pressure of the gas (P₂): ?

• Final volume of the can (V₂): 13.16 mL

Step 2: Calculate the final pressure of the gas in the can

If we assume that the gas in the can behaves as an ideal gas and that the temperature remains constant, we can calculate the final pressure of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁ / V₂

P₂ = 34.5 kPa × 473 mL / 13.16 mL = 1.24 × 10³ kPa