Question

What is the equation in slope intercept form of the line that passes through the point (2,-2) and is perpendicular to the line by y=2/5x+2

Answer 1

y= - 5/2x - 2

Explanation:

Y=2/5x + 2

Making it perpendicular, the slope will change to it's reciprocal and swap operations (+ becomes -). 2/5 will be -5/2. We already know the y-intercept which is -2, so simply put, the equation in slope-intercept form is y = -5/2x - 2

Answer 2

• y = -5/2x + 3

Explanation:

Given function:

• y = 2/5x + 2

Perpendicular lines have opposite reciprocal slopes.

The line that is perpendicular to the given will have a slope of -5/2.

Now use the point (2, -2) and point-slope form to find the equation:

• y - (-2) = -5/2(x - 2)
• y = -5/2x + 5 - 2
• y = -5/2x + 3