Question

What is an equation of the line that passes through the points (3, 2) and (6, -3)?

Answer 1

`y=-(5)/(3) x+7`

Explanation:

Calculate the slope from 2 points.

`(y_(2) - y_(1))/(x_(2) - x_(1))`

`(-3 - 2)/(6 - 3)`

`(-5)/(3)`

Substitute the slope (m) in the slope-intercept form of the equation.

`y=-(5)/(3) x`

Solve for b, which is the y-intercept of the line. Plot the line and move it to fit the points.

`y = 7`

Substitute b, into the equation.

`y=-(5)/(3) x+7`

Answer 2

y=-5/3x+7

Explanation:

-3-2/6-3= -5/3 (slope)

y=-5/3x+b

2=-5+b

b=7

y=-5/3x+7