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What is the weight in newton of a 18.0 kg bowling ball on earth's surface?

1 Answer

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Answer:

W = 176.4 N

Step-by-step explanation:

Given that,

The mass of a bowling ball, m = 18 kg

We need to find the weight of the bowling ball on Earth's surface. The weight of an object on the surface of Earth is given by :

W = mg

Where

g is the acceleration due to gravity

Put all the values,

W = 18 × 9.8

W = 176.4 N

So, the weight of the ball on Earth's surface is equal to 176.4 N.

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