Question

In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=71°, and RS = 2.5 feet. Find the length of SQ to the nearest tenth of a foot.

Answer 1

9514 1404 393

Answer:

0.9 ft

Explanation:

The relevant trig relation is ...

Tan = Opposite/Adjacent

tan(71°) = (2.5 ft)/SQ . . . . . . . . fill in the given values

SQ = (2.5 ft)/tan(71°) ≈ 0.8608 ft

The length of SQ is about 0.9 feet.