Question

Find the missing side lengths. Leave your answers as radicals in simplest form.

Please help!!!! Due today please help!!!!!!

Answer 1

`m = 10\sqrt 3`

`n = 10`

Explanation:

Required

Find m and n

Considering the given angle, we have:

`\sin(60) = (Opposite)/(Hypotenuse)`

This gives:

`\sin(60) = (m)/(20)`

Make m ths subject

`m = 20 * \sin(60)`

`\sin(60) =(\sqrt 3)/(2)`

So, we have:

`m = 20 *(\sqrt 3)/(2)`

`m = 10\sqrt 3`

Considering the given angle again, we have:

`\cos(60) = (Adjacent)/(Hypotenuse)`

This gives:

`\cos(60) = (n)/(20)`

Make n the subject

`n = 20 * \cos(60)`

`\sin(60) =(1)/(2)`

So, we have:

`n = 20 *(1)/(2)`

`n = 10`