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A student dissolves 0.250 mol NaC1 in 2.05 kg H20. What is the molality of the resulting solution? Show your work.

User Zuljin
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20 votes

Answer:

the person below me is wrong

Step-by-step explanation:

User Gregroy
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18 votes
18 votes


\boxed{\sf Molality=(Moles\:of\:solute)/(Mass\:of\: solvent\:in\;kg)}

  • Moles=0.25
  • Mass=2.5kg


\\ \rm\Rrightarrow Molality=(0.25)/(2.5)=0.1m

User Kamahl
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