Question

if the perimeter of the rectangle was known to be 90 in what would the value of x be in order for this to be true​

Answer 1

x = 30 in

Explanation:

length of rectangle is (2/3)x + 10; width is (1/3)x + 5;

perimeter is 90 in; find x:

P = 90 in = 2(2/3)x + 2(10) + 2(1/3)x + 2(5), or

90 in = (6/3)x + 30 in

Solving for x, we get (2)x = 60 in, or x = 30 in