Answer:
Hello your question has some missing data attached below is the missing data ( Note: the PH in the attached question is 3.2 but the PH value I used in the solution = 3.1 as requested in the initial question )
answer : 0.41 volts
Step-by-step explanation:
Given data :
[ Fe²⁺ ] = 1.3 M
[ Fe³⁺ ] = 0.010 M
[ H⁺ ] = 10^3.1
O2 = 0.20 atm
E⁰cell = 0.46 volts
temperature = 25°C ( room temperature )
Calculate the voltage of this ( 3 -cell battery )
we can apply the relation below
E = E⁰cell - ( 0.0591 / n )*Log Q
= 0.46 - ( 0.0591 / 4 )*Log [ (0.01)^4 / (1.3)^4 * (10^3.1)^4 * 0.2 ]
= 0.4120 Volts
Note : Q is determined from the equation attached to the question