Question

A bag contains 8 red M&Ms, 12 blue M&Ms, 3 brown M&Ms, and 7 green M&Ms. An M&M is picked at random from the bag.

What is the probability of getting the first color M&M, eating it, then grabbing the second color?

Brown, then blue:

Answer 1

4%

Explanation:

8 red + 12 blue + 3 brown + 7 green = 30 M&Ms

3 brown / 30 M&Ms = 0.1

you ate one so now you have 29 M&Ms

12 / 29 = 0.4137931034

0.1 x 0.4137931034 x 100 = 4.1379310344%

rounds to 4%

hope this helped