125k views
2 votes
A horticulturist working for a large plant nursery is conducting experiments on the growth rate of a new shrub. Based on previous research, the horticulturist feels the average weekly growth rate of the new shrub is 3cm per week. A random sample of 45 shrubs has an average growth of 1.50cm per week with a standard deviation of 3cm. Is there overwhelming evidence to support the claim that the growth rate of the new shrub is less than 3cm per week at a 0.050 significance level?

Find the value of the test statistic. Round your answer to three decimal places, if necessary.

User Moyheen
by
7.1k points

1 Answer

4 votes

Answer:

Test statistic = - 3.354

We reject H0 and conclude that the growth rate of the new shrub is less than 3cm per week.

Explanation:

H0 : μ = 3

H1 : μ < 3

The test statistic = (xbar - μ) / (s/ √n)

Xbar = 1.50

μ = 3

s = 3

n = 45

Test statistic = (1.5 - 3) / (3/ √45)

Test statistic = - 1.5 / 0.4472135

Test statistic = - 3.354

Pvalue, using the Pvalue from Z score calculator :

Pvalue = 0.00039826

α = 0.05

Pvalue < α ; We reject H0 and conclude that the growth rate of the new shrub is less than 3cm per week.

User Dnoeth
by
6.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.