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Se disuelven 10 g de acido carbónico H2CO3 en 150 g de agua. Determina la concentración % m/m de esa disolución?

User Christok
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The question is: 10 g of carbonic acid H2CO3 are dissolved in 150 g of water. Determine the% m / m concentration of that solution?

Answer: The% m / m concentration of that solution is 6.66%.

Step-by-step explanation:

Given: Mass of solute = 10 g

Mass of solvent = 150 g

Formula used to calculate the %m/m is as follows.


Percent (m/m) = (mass of solute)/(mass of solvent) * 100

Substitute the values into above formula as follows.


Percent (m/m) = (mass of solute)/(mass of solvent) * 100\\= (10 g)/(150 g) * 100\\= 6.66%

Thus, we can conclude that the% m / m concentration of that solution is 6.66%.

User Kepkin
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