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14 votes
Question:

Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form.

User Studentbi
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2 Answers

12 votes
12 votes
The answer is y = -2/5x - 0.2
User Sevenflow
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12 votes
12 votes

Answer:

y = -(2/5)x -1/5

Explanation:

slope = (y2-y1)/(x2-x1)

and line equation is y = mx +b, where m is slope and b is y intercept value when x = 0.

Given:

point1 = (-3, 1) and point2 = (2, -1)

We can find the slope as m = (1+1)/(-3-2) => 2/-5 => -(2/5)

y = -(2/5)x + b

Now use one of the point to find b.

1 = -(2/5)(-3) + b => 1 = 6/5 + b => 1-6/5 =b

b= -1/5

Therefore, the final equation for the line is

y = -(2/5)x -1/5

User AkshayP
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