Question

A point charge at the origin of a coordinate system produces the electric field E=(56,000 N/C) x on the x-axis at the location x=-0.65m. Determine the sign and magnitude of the charge.

Answer 1

q = 1.95 x 10⁻⁶ C = 1.95 μC

Step-by-step explanation:

The formula for the electric field produced by a point charge is given as follows:

`E = (kq)/(r^2)\\`

where,

E = Electric Field strength = 56000 N/C

k = Colomb's Constant = 9 x 10⁹ Nm²/C²

q = magnitude of charge = ?

r = distance = 0.65 m

Therefore,

`56000\ N/C = ((9\ x\ 10^9\ Nm^2/C^2)q)/((0.56\ m)^2)\\\\q = ((56000\ N/C)(0.56\ m)^2)/(9\ x\ 10^9\ Nm^/C^2)\\\\`

q = 1.95 x 10⁻⁶ C = 1.95 μC