Question

May someone assist, please...? I don't know how to do chemistry work...

1) How many mL of 5.00M CaSO4 solution must be


diluted with water to prepare 500.0 mL of 0.900M CaSO4?


2) 20.0 mL of a stock solution of NaOH is diluted with water to prepare 150.0mL of 1.50 M NaOH solution.


Calculate the Molarity of the stock NaOH solution?


3) 12.00 mL of 3.50 M NaOH solution is diluted with 88.0 mL of water.


What is the concentration of sodium hydroxide in the diluted solution?


4) 9.0 mL of 8.0 M HCl solution is diluted with water to prepare 0.50 M HCl solution. What is the final volume of this solution?

Answer 1

All questions can be solved by C1V1=C2V2

1) 5.00M x V1 = 0.900M x 500.0 mL

V1= 90 ml

therefor you need to add 500 - 90 = 410.0 ml

2) 20.0 mL x C1 = 150.0mL x 1.50 M

C1= 11.25 M

3) 12.00 mL x 3.50 M = 100.0 mL x C2

C2= 0.42 M

4) 9.0 mL x 8.0 M = 0.50 M x V2

V2 = 144 ml