Explanation:
a) $11 = 3 lines of a classified ad
$x = 2 limes of a classified ad
cross multiply
3x = 22
divide by the coefficient of x
which is 3
3x/3 = 22/3
x = 7.33 approximately 7
x = 7.
b) $11 = 3 lines of a classified ad
$x = 5 lines of a classified ad
cross multiply
3x = 55
diviee by the coefficient of x
which is 3
3x/3 = 55/3
x =18.33 approximately 18
x =18.