Answer:
molarity = moles of solute/liters of solution
0.25 M NaOH = 0.25 mol NaOH/L
mass = moles (n) × molar mass (M)
n(NaOH) = 0.25 mol
M(NaOH) = 39.997 g/mol
m(NaOH) = 0.25 mol × 39.997 g/mol = 9.999 g
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