Question

A chemist has three different acid solutions. The first acid solution contains 25%

acid, the second contains 40% and the third contains 80% . They want to use all three solutions to obtain a mixture of 96 liters containing 55% acid, using
3 times as much of the 80% solution as the 40% solution. How many liters of each solution should be used?

Answer 1

Solution:
Let the volume (in litres) of acids used be:
x1=amount of 25% acid
x2=amount of 40% acid
x3=3*x2=amount of 60% acid