Question

A narrow slit is illuminated with light of wavelength 410 nm. If the central maximum extends to ±35.0°, how wide is the slit

Answer 1

The wide of the slit is 0.715 μm.

Explanation:

We can use the single slit diffraction equation.

`d\cdot sin(\theta)=\lambda`

Where:

• d is the wide of the slit
• θ is the angle of the maximum central diffraction intensity (we use th epossitve value 35°)
• λ is the wavelength

We just need to solve this equation for d.

`d=(\lambda)/(sin(\theta))`

`d=(410*10^(-9))/(sin(35))`

`d=7.15*10^(-7)\: m`

Therefore, the wide of the slit is 0.715 μm.

I hope it helps you!