Question

How big of an electric field exists when an electric force of 2 Newtons is exerted on a charge of 1.602 x 10^-19 Coulombs? *

Answer 1

The electric field experienced by the charge is 1.248 x 10¹⁹ N/C

Explanation:

Given;

the magnitude of the force, F = 2 N

the magnitude of the charge, q = 1.602 x 10⁻¹⁹ C

The electric field experienced by the charge is calculated as follows;

`E = (F)/(q) \\\\E = (2)/(1.602 * 10^(-19) \ ) \\\\E = 1.248 * 10^(19) \ N/C`

Therefore, the electric field experienced by the charge is 1.248 x 10¹⁹ N/C.