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Tim, Rita, and Moby play a game of chance. If they play 63 times, and they each have an equal chance of winning, Moby will likely win how many times? (Help me ASAP pls)
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Tim, Rita, and Moby play a game of chance. If they play 63

times, and they each have an equal chance of winning,
Moby will likely win how many times?
(Help me ASAP pls)

User Michael Fehr
by
7.8k points

1 Answer

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Answer: is b.21

Explanation:

I found the questions. 63/3=21

Tim, Rita, and Moby play a game of chance. If they play 63 times, and they each have-example-1
User Tally
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