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What is the surface area of a cylinder with radius x + 3 and height x + 11?

User Pistos
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2 Answers

1 vote

Final answer:

The surface area of a cylinder with radius x + 3 and height x + 11 is calculated using the formula A = 2πr² + 2πrh, leading to A = 4πx² + 40πx + 84π.

Step-by-step explanation:

To find the surface area of a cylinder with a radius of x + 3 and a height of x + 11, you can use the formula for surface area of a cylinder, which is A = 2πr² + 2πrh. This formula combines the areas of the two circular end-caps and the rectangular wrap which forms the curved surface area when rolled up.

Substituting the given radius and height into the formula gives us:


Upon expanding the terms, you will get:


Combining like terms, we find:



Therefore, the surface area of the given cylinder is 4πx² + 40πx + 84π, where π is approximately 3.1415927.

User SciPhi
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4.7k points
3 votes

Answer:

A≈263.89

Step-by-step explanation:

Solution

A=2πrh+2πr2=2·π·3·11+2·π·32≈263.89378

User Dardan Iljazi
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4.5k points