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If 7sin²∅+3cos²∅is equal to 4,then evaluate sec∅+cosec∅​

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3 votes

Answer:


\sec \theta + \csc \theta = (2\cdot √(3)+6)/(3)

Explanation:

We proceed to simplify the given trigonometric expression into a form with a single trigonometric function:

1)
7\cdot \sin^(2)\theta + 3\cdot \cos^(2)\theta = 4 Given.

2)
4\cdot \sin^(2)\theta + 3\cdot (\sin^(2)\theta + \cos^(2)\theta) = 4 Definition of addition/Associative and distributive properties.

3)
4\cdot \sin^(2) \theta +3 = 4
\sin^(2)\theta + \cos^(2)\theta = 1/Modulative property

4)
4\cdot \sin^(2)\theta = 1 Compatibility with addition/Existence of additive inverse/Modulative property

5)
\sin \theta = (1)/(2) Compatibility with multiplication/Existence of multiplicative inverse/Modulative property/Definition of division

6)
\theta = \sin^(-1) (1)/(2) Inverse trigonometric inverse.

7)
\theta = 30^(\circ) Result.

By Trigonometry, we know that secant and cosecant functions have the following identities:


\sec \theta = (1)/(\cos \theta),
\csc \theta = (1)/(\sin \theta) (1, 2)

In addition, we know that
\sin 30^(\circ) = (1)/(2) and
\cos 30^(\circ) = (√(3))/(2), then the sum of the two trigonometric function abovementioned is:


\sec \theta + \csc \theta = (1)/(\cos \theta) + (1)/(\sin \theta)


(2)/(√(3)) + 2 = (2\cdot √(3))/(3) + 2


\sec \theta + \csc \theta = (2\cdot √(3)+6)/(3)

User Dannyu NDos
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