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What is an equation of the line that passes through the point (2,−6) and is parallel to the line x−2y=8?

User Tousif
by
6.6k points

1 Answer

10 votes

Answer:

y = x/2 - 7

Explanation:

First, we need to find the slope of the given equation: x - 2y = 8

Subtract x from both sides

x - 2y = 8

- x - x

-2y = 8 - x

Divide both sides by -2

-2y/-2 = (8 - x)/-2

y = -4 + x/2

The slope of this equation is 1/2

So the equation of our parallel equation is y = x/2 + b

We have to find b, so plug in the given coordinates

-6 = 2/2 + b

-6 = 1 + b

Subtract 1 from both sides

-6 = 1 + b

- 1 - 1

b = -7

Plug it back into the original equation

y = x/2 - 7

User ElChiniNet
by
6.4k points
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