Question

If a body is thrown up with an initial velocity 'u' and covers a maximum height of 'h' , then 'h' is equal to u²/2g

Explain in detail.​

Answer 1

1/2 m u^2 initial Kinetic Energy of body

m g h Potential Energy body attains as it rises to height

1/2 m u^2 = m g h conversion of KE to PE

h = u^2 / ( 2 g)