Question

A 1.0 liter flask contains 90.1 moles of water vapor at 27.0 oC. What is the pressure of the gas?

Answer 1

The pressure of the gas is 224839.8 atm

Step-by-step explanation:

As we know

PV = nRT

Substituting the given values, we get -

P * 1 L = 90.1 moles * 8.314 4621(75). J K−1 mol−1 * 300

P = 224839.8 atm

The pressure of the gas is 224839.8 atm