Question

5. How many grams of cuso4 are needed to prepare 100. Ml of a 0. 10 m solution?.

Answer 1

Remember that there are 5 moles of water for every 1 mole of hydrate

159.61g mol−1(159.61+5×18.015)g mol−1×100=63.92% CuSO4

This tells you that for every 100 g of copper(II) sulfate pentahydrate, you get 63.92 g of anhydrous copper(II) sulfate. Use this as a conversion factor to get

1.596g CuSO4⋅100 g CuSO4⋅5H2O63.92g CuSO4=2.497 g CuSO4⋅5H2O

Rounded to two sig figs, the answer will be