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Determine the center and radius of the following circle equation: x ^ 2 + y ^ 2 - 6x + 2y - 39 = 0
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Determine the center and radius of the following circle equation: x ^ 2 + y ^ 2 - 6x + 2y - 39 = 0

User Shyam Narayan
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x^2-6x+y^2+2y-39=0 =(x-3)^2 -9 + (y+1)^2 -1-39=0 so (x-3)^2 + (y+1)^2 = 49 . The center is at (3,-1) and the radius is 7 units.
User RyanQuey
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