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In a class of 29 students, 20 have a brother and 8 have a sister. There are 3 students who do not have any siblings. What is the probability that a student chosen randomly from the class is an only child?

User Equanimity
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2 Answers

4 votes

Answer: 1/4 = 0.25 = 25%

Explanation:

Let x be the number of students having both brother and sister.

Brother only is 9-x

Sister only is 16-x

Brother only + sister only + both + neither = 28

(9-x) + (16-x) + x + 7 = 28

32 - x = 28

x = 4

The probability per the diagram is 4/16 = 1/4

Per definition of conditional probability:

prob( brother | sister) = prob ( brother AND sister) / prob ( sister)

= 4/16 = 1/4

1/4 = 0.25 = 25%

User Sergei Chicherin
by
3.3k points
3 votes

Answer:

3/29

Explanation:

It's right trust me.

User Cedias
by
3.1k points