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What is the equation of the circle with center (2,-5) that passes through the point (-2,10). (x-2) ^2 + (y+5)^2=25 (x+2) ^2 +(y-5)^2=241 (x-2)^2 +(y-5)^2=241 (x+2)^2 + (y-5)^2=25
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What is the equation of the circle with center (2,-5) that passes through the point (-2,10).

(x-2) ^2 + (y+5)^2=25
(x+2) ^2 +(y-5)^2=241
(x-2)^2 +(y-5)^2=241
(x+2)^2 + (y-5)^2=25

User RickJames
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1 Answer

5 votes

Answer:

b is the answer

Explanation:

User Souvik Ray
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4.8k points
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