Question

Solve the quadratic equation
8x^2+16x+8=0

Answer 1

8x²+16x+8=0

x²+2x+1=0

D=4-4=0

x0=-2/2=-1

Answer 2

x = -1

Explanation:

`8x^2+16x+8=0` {divide both sides by 8}

`x^2+2x+1=0\\\\a=1\,,\quad b=2\,,\quad c=1\\\\x=(-2\pm√(2^2-4\cdot1\cdot1))/(2\cdot1)=\frac{-2\pm√(4-4)}2=\frac{-2\pm0}2=-1`