Examine the balanced equation for the reaction between lead(I) nitrate and sodium chloride.
Pb(NO3)2 + 2NaCl → 2NaNO3 + PbCl2
If 10.0 g of sodium chloride react with excess lead(II) nitrate, what mass of lead(II) chloride will be produced?
0 20.8 g
O 23.8 g
O 47.68
O 95.28