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A gas occupies 450. mL 3 atm. If its volume decreases to 0.200 L then what will its new pressure be?

Assume constant temperature and mass.

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1 Answer

3 votes

Answer:

6.75 sym.

Step-by-step explanation:

Boyle's Law: The pressure of a gas in an enclosed container with a flexible volume is inversely proportional to the volume occupied by the gas.

Empirically => P ∝ 1/V => P = k(1/V) => k = P·V

For any conditions of Pressure & Volume, Pressure x Volume is a constant.

Therefore, k₁ = k₂ => P₁V₁ = P₂V₂ => V₂ = P₁V₁ / V₂

=> V₂ = (3atm)(0.450L)/(0.200L) = 6.75 atm.

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