Final answer:
The change in the jogger's internal energy, after doing 3.45 E 6 J of work and giving off 1.67 E 6 J of heat, is a decrease of 5.12 E 6 J.
Step-by-step explanation:
The question involves the concept of internal energy change in a physical system, which relates to the first law of thermodynamics. The law states that the change in internal energy of a system (ΔU) is equal to the heat added to the system (Q) minus the work done by the system (W). For the jogger, the work done (3.45 E 6 J) and the heat given off (1.67 E 6 J) can be used to calculate the change in internal energy using the formula:
ΔU = Q - W
To find the change in internal energy of the jogger, we would subtract the work done from the heat given off. Since the work is being done by the jogger, it is energy leaving the system, and the heat given off is also energy leaving the system, it should be:
ΔU = -1.67 E 6 J - 3.45 E 6 J
ΔU = -5.12 E 6 J
Therefore, the change in the jogger's internal energy is a decrease of 5.12 E 6 J.