Answer:
c. 143.8 m³
Explanation:
The figure can be decomposed into a semicircle and a trapezoid
Area = area of semicircle + area of trapezoid
= ½(πr²) + ½(a + b)h
Where,
r = ½(9) = 4.5 m
a = 9 m
b = 23 m
h = 7 m
Area of the figure = ½(π*4.5²) + ½(9 + 23)7
Area of the figure = 31.81 + 112
= 143.8 m³