Answer:
The ratio of the new volume to the old volume is 8 to 1.
Step-by-step explanation:
Let's first list what we know:
- A cube has sides with lengths of 4 m
- The volume of the cube is 64
![m^3](https://img.qammunity.org/2022/formulas/physics/high-school/78b4p02kc2egtpcmbtwfix95tkx9fzmllt.png)
- The new cube has sides double the length of the old cube
Since the new cube has sides double the length of the sides of the old cube, and 4 doubled is 8, the length of the sides of the new cube is 8.
The equation for the volume of a cube is
, where "V" is the volume and "s" is the lengths of the sides.
Now, let's solve for the volume of the new cube:
![V = s^3](https://img.qammunity.org/2022/formulas/physics/college/4iwyreshcfoexclsu1yxp6xlrq4enjfmvu.png)
![V = 8^3](https://img.qammunity.org/2022/formulas/physics/college/dsri2b35y8mttb2buuqqqljd8blp344pfk.png)
![V = 512](https://img.qammunity.org/2022/formulas/physics/college/ra8mhh2f4yh6glvxi9cge8sw6rtdvyahsc.png)
The volume of the new cube is 512
.
The ratio of the new volume to the old volume is 512 : 64.
Let's simplify the ratio:
512 : 64
8 : 1
The ratio of the new volume to the old volume is 8 to 1.
P.S. This question should be in the mathematics subject, not the physics subject. (I pretty much only do math problems, so yes, it does matter. I don't know about the others though.)