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The angle of elevation of the top of a tower from two points 121 m and 144 m away from the foot of the tower on th same side are found to be complementary. find the height of the tower.​

User Mettleap
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1 Answer

5 votes

Answer:

132 m

Explanation:

Refer to attachment for figure.

In smaller triangle with angle theta , we have ,

⇒ tanθ = p/b

⇒ tanθ = h/121m

tanθ = h/121 m

In triangle with angle 90-

⇒ tan(90-θ) = p/b

⇒ cot θ = h/144 m

Multiplying these two ,

=> tanθ . cotθ = h/121 m × h/144m

=> 1 = h²/ (121 m × 144m )

=> h² = 121m × 144m

=> h= √ ( 121m × 144m)

=> h = 11m × 12m

=> h = 132 m

The angle of elevation of the top of a tower from two points 121 m and 144 m away-example-1
User Fabio Fantoni
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