Answer:
28.15 cm²
Explanation:
In ΔNOP, n = 7.4 cm, o = 8.7 cm and ∠P=61°. Find the area of ΔNOP, to the nearest 10th of a square centimeter
For the above question, we are given 2 sides and an angle.
The formula to find the area of ΔNOP
1/2 × a × b × sin θ
From the above question:
θ = 61°
a = 7.4 cm
b = 8.7 cm
Hence,
1/2 × 7.4 × 8.7 × sin 61
= 28.154008373 cm²
Approximately to the nearest tenth = 28.15 cm²