Question

Calculate the value of Delta H for the reaction CaCO3 --> CO2 + CaO from the following enthalpy changes:

Ca + C + 3/2 O2 --> CaCO3 ΔH = -1206.9 kJ
Ca + ½ O2 --> CaO ΔH = -635.1 kJ
C + O2 -->CO2 ΔH= - 393.5 kJ

Answer 1

Step-by-step explanation:

crescents discuss wentz eg

Answer 2

2,2,1,2

2 Ca + 2 CO2 + 1 O2 → 2 CaCO3

Step-by-step explanation:

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