Answer:
The process of nerve impulse transmission by means of an action potential involves the processes of depolarization, repolarization, hyperpolarization and restoration of resting memebrane potential.
Step-by-step explanation:
In order for a neuron to receive and transmit a message it must be in a polarized state. While in this rest state there are more sodium ions outside the cell membrane while potassium is prevalent inside the cell. This causes the neuron to maintain a neutral charge. Once the action potential arrives at its dendrites, a nerve cell will shuttle the message down its own axon and to the next neuron via its axon terminal. This impulse will cause the cell to become depolarized and will effectively change the charge of the neuron to a poositive charge. After sodium rushes into the cell, the potassium will rush out in order to restore its resting memebrane potential. Once the impulse reaches the axon terminal, it is used to open voltage- gated calcium channels releasing calcium ions that stimulates a neurotransmitter to continue the message to the next neuron. The neuron then undergoes a repolarisation when all ions are repositioned with help of the voltage-gated ion channels.