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A proton is moved so that its electric potential energy increases from 2.0 × 10-18 J to 6.0 × 10-18 J. The magnitude of the charge on a proton is 1.602 × 10-19 C.

The electric potential difference through which the proton moved, to the nearest whole number, is
V.

User Eileen Tao
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1 Answer

4 votes

Answer:

25v

Step-by-step explanation:

right on edge

User Omer Tuchfeld
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